Solution 7 (a).
See text and/or instructor's solution manual.
Answer.
.
Solution. Given
the power series
.
By Taylor's
Theorem,
.
Therefore,
, so
that
.
We are done.
We can expand the series in its even and odd terms
![[Graphics:../Images/TaylorSeriesModHome_gr_532.gif]](../Images/TaylorSeriesModHome_gr_532.gif)
We are really done.
Aside. We can let Mathematica double check our work.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell