Solution 9 (a).

See text and/or instructor's solution manual.

Solution.   Observe that

                    [Graphics:../Images/TaylorSeriesModHome_gr_640.gif]  

Change the index of summation in the series and write it as follows

                    [Graphics:../Images/TaylorSeriesModHome_gr_641.gif]  

Now use the relation   [Graphics:../Images/TaylorSeriesModHome_gr_642.gif]   for  [Graphics:../Images/TaylorSeriesModHome_gr_643.gif]  to get  

                    [Graphics:../Images/TaylorSeriesModHome_gr_644.gif]

Thus we have,   [Graphics:../Images/TaylorSeriesModHome_gr_645.gif].   

Rearrange the terms,   [Graphics:../Images/TaylorSeriesModHome_gr_646.gif],   and solve for  [Graphics:../Images/TaylorSeriesModHome_gr_647.gif].

Therefore,   [Graphics:../Images/TaylorSeriesModHome_gr_648.gif],   for all  [Graphics:../Images/TaylorSeriesModHome_gr_649.gif]  for some number  R.

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/TaylorSeriesModHome_gr_650.gif]

[Graphics:../Images/TaylorSeriesModHome_gr_651.gif]

The coefficients  [Graphics:../Images/TaylorSeriesModHome_gr_652.gif]  can be defined recursively with the following commands:

 

[Graphics:../Images/TaylorSeriesModHome_gr_653.gif]

A table of the first few values can be displayed:

[Graphics:../Images/TaylorSeriesModHome_gr_654.gif]

[Graphics:../Images/TaylorSeriesModHome_gr_655.gif]


[Graphics:../Images/TaylorSeriesModHome_gr_656.gif]

[Graphics:../Images/TaylorSeriesModHome_gr_657.gif]

We are really done.   

Aside.  It is known that the Fibonacci numbers can be represented with the formula:

                    [Graphics:../Images/TaylorSeriesModHome_gr_658.gif].  

 

[Graphics:../Images/TaylorSeriesModHome_gr_659.gif]

[Graphics:../Images/TaylorSeriesModHome_gr_660.gif]


[Graphics:../Images/TaylorSeriesModHome_gr_661.gif]

[Graphics:../Images/TaylorSeriesModHome_gr_662.gif]

It in interesting to notice that Mathematica can sum the infinite series:

[Graphics:../Images/TaylorSeriesModHome_gr_663.gif]

[Graphics:../Images/TaylorSeriesModHome_gr_664.gif]

Notice.  Mathematica prefers to write   [Graphics:../Images/TaylorSeriesModHome_gr_665.gif]   as   [Graphics:../Images/TaylorSeriesModHome_gr_666.gif].

 

We are really really done.   

 

Resolving the formula for the Fibonicci Numbers.  

It is not too difficult a task to expand  [Graphics:../Images/TaylorSeriesModHome_gr_667.gif]  in its partial fraction form:

                    [Graphics:../Images/TaylorSeriesModHome_gr_668.gif].  

The two terms   [Graphics:../Images/TaylorSeriesModHome_gr_669.gif]   and   [Graphics:../Images/TaylorSeriesModHome_gr_670.gif]   on the right side of this equation can easily be expanded as geometric series:

                    [Graphics:../Images/TaylorSeriesModHome_gr_671.gif],   and

                    [Graphics:../Images/TaylorSeriesModHome_gr_672.gif].  

Then we can substute these series and obtain

                    [Graphics:../Images/TaylorSeriesModHome_gr_673.gif]   

Therefore,  we have shown that  [Graphics:../Images/TaylorSeriesModHome_gr_674.gif].

 

 

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell