Exercise 9. Find
the temperature function
in the first quadrant
,
that satisfies the following boundary conditions (shown in Figure
11.29).
Solution 9.
See text and/or instructor's solution manual.
Answer. ![]()
.
A Short
Solution. Map the quadrant onto the upper
half-plane with the function
, then
multiply the boundary values in Example 11.17 by 75
and consider
, then
construct
.
A Longer
Solution. The
transformation
maps
the first quadrant
,
onto the upper half plane
where
the boundary values are
Use the result in Example 11.17 where we found that the
function
has
the boundary values
We can easily obtain
by multiplying
by 75 and
adding 25,
.
Now construct
Therefore,
.
We are done.
For computational purposes we can use the formulas for the real
and imaginary parts of
, that
were derived in Section
10.4.
.
In particular,
(10-26)
.
If an explicit solution is required, then we can use Formula
(10-26) in Section
10.4 and write
,
where the function
has
range values satisfying
.
Now make the substitution
and
and
.
Thus,
Therefore,
.
We are really done.
Aside. We can
graph the function
.
![[Graphics:../Images/TemperaturesModHome_gr_499.gif]](../Images/TemperaturesModHome_gr_499.gif)
A
contour graph of the function
,
where
for
.
![[Graphics:../Images/TemperaturesModHome_gr_503.gif]](../Images/TemperaturesModHome_gr_503.gif)
A
graph of the function
,
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell