Exercise 2.  Find the temperature function [Graphics:Images/TemperaturesModHome_gr_93.gif] in the infinite strip bounded by the lines   [Graphics:Images/TemperaturesModHome_gr_94.gif],  

that satisfies the following boundary values (shown in Figure 11.22).

                    [Graphics:Images/TemperaturesModHome_gr_95.gif]  

Solution 2.

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/TemperaturesModHome_gr_96.gif].  

Solution.   The mapping  [Graphics:../Images/TemperaturesModHome_gr_97.gif]  will map the given domain

onto the infinite strip [Graphics:../Images/TemperaturesModHome_gr_98.gif].   The new boundary value problem for  [Graphics:../Images/TemperaturesModHome_gr_99.gif] is

                    [Graphics:../Images/TemperaturesModHome_gr_100.gif]

The method in Example 11.14 (compare with Exercise in Section 11.2) can be used to construct the solution in the w-plane

                    [Graphics:../Images/TemperaturesModHome_gr_101.gif]    where    [Graphics:../Images/TemperaturesModHome_gr_102.gif],  [Graphics:../Images/TemperaturesModHome_gr_103.gif],  [Graphics:../Images/TemperaturesModHome_gr_104.gif],   [Graphics:../Images/TemperaturesModHome_gr_105.gif].  

Making these substitutions and get   [Graphics:../Images/TemperaturesModHome_gr_106.gif],   which can be simplified as   [Graphics:../Images/TemperaturesModHome_gr_107.gif].  

Now use the substitution   [Graphics:../Images/TemperaturesModHome_gr_108.gif]  and  [Graphics:../Images/TemperaturesModHome_gr_109.gif]   to obtain the solution in the z-plane  

                    [Graphics:../Images/TemperaturesModHome_gr_110.gif]   

Therefore,  

                    [Graphics:../Images/TemperaturesModHome_gr_111.gif].  

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/TemperaturesModHome_gr_112.gif]

[Graphics:../Images/TemperaturesModHome_gr_113.gif]


[Graphics:../Images/TemperaturesModHome_gr_114.gif]

[Graphics:../Images/TemperaturesModHome_gr_115.gif]


[Graphics:../Images/TemperaturesModHome_gr_116.gif]

[Graphics:../Images/TemperaturesModHome_gr_117.gif]

We are really done.   

 

Aside.  For illustration purposes we can graph the function   [Graphics:../Images/TemperaturesModHome_gr_118.gif].   

                     [Graphics:../Images/TemperaturesModHome_gr_119.gif]

                     A contour graph of the function   [Graphics:../Images/TemperaturesModHome_gr_120.gif]

                     where   [Graphics:../Images/TemperaturesModHome_gr_121.gif]   for   [Graphics:../Images/TemperaturesModHome_gr_122.gif].  

                     [Graphics:../Images/TemperaturesModHome_gr_123.gif]

                     A contour graph of the function   [Graphics:../Images/TemperaturesModHome_gr_124.gif]

                     where   [Graphics:../Images/TemperaturesModHome_gr_125.gif]   for   [Graphics:../Images/TemperaturesModHome_gr_126.gif].  

 

                    [Graphics:../Images/TemperaturesModHome_gr_127.gif]

                    A graph of the function   [Graphics:../Images/TemperaturesModHome_gr_128.gif].  

                    [Graphics:../Images/TemperaturesModHome_gr_129.gif]  

                    [Graphics:../Images/TemperaturesModHome_gr_130.gif]

                    A graph of the function   [Graphics:../Images/TemperaturesModHome_gr_131.gif].  

                    [Graphics:../Images/TemperaturesModHome_gr_132.gif]  

 

















 

This solution is complements of the authors.

 



































 

(c) 2008 John H. Mathews, Russell W. Howell