Exercise 5.  Find the temperature function [Graphics:Images/TemperaturesModHome_gr_242.gif] in the semi-infinite strip  [Graphics:Images/TemperaturesModHome_gr_243.gif],  

that satisfies the following boundary values (shown in Figure 11.25).  

                    [Graphics:Images/TemperaturesModHome_gr_244.gif]  

Solution 5.

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/TemperaturesModHome_gr_245.gif].

Solution.   The transformation  [Graphics:../Images/TemperaturesModHome_gr_246.gif]  maps the semi-infinite strip  [Graphics:../Images/TemperaturesModHome_gr_247.gif]

onto the upper half plane  [Graphics:../Images/TemperaturesModHome_gr_248.gif]   where the boundary values are

                    [Graphics:../Images/TemperaturesModHome_gr_249.gif]   

Apply Theorem 11.2 in Section 11.2 to construct a Dirichlet solution in the upper half-plane

use formula (11-5)   [Graphics:../Images/TemperaturesModHome_gr_250.gif]   with   [Graphics:../Images/TemperaturesModHome_gr_251.gif],  

                    [Graphics:../Images/TemperaturesModHome_gr_252.gif].  

Now we substitute   [Graphics:../Images/TemperaturesModHome_gr_253.gif]   and   [Graphics:../Images/TemperaturesModHome_gr_254.gif]   to obtain  

                    [Graphics:../Images/TemperaturesModHome_gr_255.gif]   

Therefore,   

                    [Graphics:../Images/TemperaturesModHome_gr_256.gif].  

Now use   [Graphics:../Images/TemperaturesModHome_gr_257.gif]   and construct the solution.

Therefore,   

                    [Graphics:../Images/TemperaturesModHome_gr_258.gif].    

Use Identity  (5-34)   [Graphics:../Images/TemperaturesModHome_gr_259.gif]  and get  

                    [Graphics:../Images/TemperaturesModHome_gr_260.gif]     

Therefore,   

                    [Graphics:../Images/TemperaturesModHome_gr_261.gif].   

 

We are done.   

 

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/TemperaturesModHome_gr_262.gif]

[Graphics:../Images/TemperaturesModHome_gr_263.gif]

We are really done.   

 

Aside.  For illustration purposes we can graph the function   [Graphics:../Images/TemperaturesModHome_gr_264.gif].   

                     [Graphics:../Images/TemperaturesModHome_gr_265.gif]

                     A contour graph of the function   [Graphics:../Images/TemperaturesModHome_gr_266.gif]   

                     where   [Graphics:../Images/TemperaturesModHome_gr_267.gif]   for   [Graphics:../Images/TemperaturesModHome_gr_268.gif].  

 

                     [Graphics:../Images/TemperaturesModHome_gr_269.gif]

                     A graph of the function   [Graphics:../Images/TemperaturesModHome_gr_270.gif],  

                    [Graphics:../Images/TemperaturesModHome_gr_271.gif]  

 

We are really really done.   

 

Aside.  We can also graph the intermediate function   [Graphics:../Images/TemperaturesModHome_gr_272.gif]

                     [Graphics:../Images/TemperaturesModHome_gr_273.gif]

                    A contour graph of the intermediate function   [Graphics:../Images/TemperaturesModHome_gr_274.gif].

                    where   [Graphics:../Images/TemperaturesModHome_gr_275.gif]   for   [Graphics:../Images/TemperaturesModHome_gr_276.gif].  

 

                     [Graphics:../Images/TemperaturesModHome_gr_277.gif]

                    A graph of the intermediate function   [Graphics:../Images/TemperaturesModHome_gr_278.gif],

                    [Graphics:../Images/TemperaturesModHome_gr_279.gif]   

 

















 

This solution is complements of the authors.

 



































 

(c) 2008 John H. Mathews, Russell W. Howell