Exercise 7. Suppose
that the sequences of functions
and
converge
uniformly on the set T.
7 (b). Show by
example that it is not necessarily the case
that
converges
uniformly to
on
the set T.
Solution 7 (b).
See text and/or instructor's solution manual.
Solution. For
all n, let
, for
all
, where T is
the set of complex numbers.
Then
converges
uniformly to
, and
converges
uniformly to
(verify
these statements).
Show
converges
uniformly to
.
Let
be any integer greater than
, then
and
.
Therefore, for
, we
have
for
all
.
Show
converges
uniformly to
.
Let
be any integer greater than
, then
and
.
Therefore, for
, we
have
for
all
.
However, even
though
converges
pointwise to
(explain
why),
the convergence is not uniform (verify).
Convergence is pointwise.
Let
.
Fix the value
. Now
choose
to be the smallest integer satisfying
.
Then for any
we
will have
and
which
implies
and
which
implies
and
.
Hence, for any
we
obtain
![[Graphics:../Images/UniformConvergenceModHome_gr_326.gif]](../Images/UniformConvergenceModHome_gr_326.gif)
Therefore,
converges
pointwise to
on
the set T.
Convergence is not uniform.
Let
.
Then for every positive integer n, if
, then
.
Thus Statement (7-3) is
satisfied:
(7-3) There
exists an
, such
that for all positive integers N,
there
is some
and
some ![]()
such
that
.
Therefore,
does
not converge uniformly
to
on
the set T.
We are
done.
Can you come up with a different example ?
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell