Example 9.15
(a). Use
z-transform
methods to solve
with
.
Explore Solution 9.15 (a).
It is worthwhile to point out how Mathematica can do the important step using residues.
![[Graphics:../Images/ZTransformDEMod_gr_171.gif]](../Images/ZTransformDEMod_gr_171.gif)
To solve
with
, we
will use our Mathematica subroutine
for
finding the solution to
. It
will take the z-transforms of each term; solve
for
; and
it's inverse
. The
format of the subroutine call is
with
.
![[Graphics:../Images/ZTransformDEMod_gr_181.gif]](../Images/ZTransformDEMod_gr_181.gif)
![[Graphics:../Images/ZTransformDEMod_gr_182.gif]](../Images/ZTransformDEMod_gr_182.gif)
To solve
with
, we
will use our Mathematica subroutine
for
finding the solution to
. It
will take the z-transforms of each term; solve
for
; and
it's inverse
. The
format of the subroutine call is
with
.
![[Graphics:../Images/ZTransformDEMod_gr_192.gif]](../Images/ZTransformDEMod_gr_192.gif)
![[Graphics:../Images/ZTransformDEMod_gr_193.gif]](../Images/ZTransformDEMod_gr_193.gif)
![[Graphics:../Images/ZTransformDEMod_gr_195.gif]](../Images/ZTransformDEMod_gr_195.gif)
![[Graphics:../Images/ZTransformDEMod_gr_196.gif]](../Images/ZTransformDEMod_gr_196.gif)