Example 9.15
(b). Use
z-transform
methods to solve
with
.
Explore Solution 9.15 (b).
It is worthwhile to point out how Mathematica can do the important step using residues.
![[Graphics:../Images/ZTransformDEMod_gr_198.gif]](../Images/ZTransformDEMod_gr_198.gif)
To solve
with
, we
will use our Mathematica subroutine
for
finding the solution to
. It
will take the z-transforms of each term; solve
for
; and
it's inverse
. The
format of the subroutine call is
with
and
.
![[Graphics:../Images/ZTransformDEMod_gr_209.gif]](../Images/ZTransformDEMod_gr_209.gif)
![[Graphics:../Images/ZTransformDEMod_gr_210.gif]](../Images/ZTransformDEMod_gr_210.gif)
![[Graphics:../Images/ZTransformDEMod_gr_212.gif]](../Images/ZTransformDEMod_gr_212.gif)
![[Graphics:../Images/ZTransformDEMod_gr_213.gif]](../Images/ZTransformDEMod_gr_213.gif)