Exercise 7.  Solve the nonhomogeneous difference equations.  

Exercise 7 (b).  [Graphics:Images/ZTransformDEModHome_gr_1487.gif]   with   [Graphics:Images/ZTransformDEModHome_gr_1488.gif].   
                          Hint.  Get  [Graphics:Images/ZTransformDEModHome_gr_1489.gif].  

Solution 7 (b).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ZTransformDEModHome_gr_1598.gif].  

Remark.   The preferred method to use involves Z-transforms, limits and residues.  

Solution.   Take the z-transform of both sides and use the initial conditions   [Graphics:../Images/ZTransformDEModHome_gr_1599.gif]:  

                    [Graphics:../Images/ZTransformDEModHome_gr_1600.gif],  

and then get    

                    [Graphics:../Images/ZTransformDEModHome_gr_1601.gif].  

New solve for  [Graphics:../Images/ZTransformDEModHome_gr_1602.gif]  and obtain:    

                    [Graphics:../Images/ZTransformDEModHome_gr_1603.gif].  

Using Tables.   Using Table 9.1 and the formulas   [Graphics:../Images/ZTransformDEModHome_gr_1604.gif]   we get:  

                    [Graphics:../Images/ZTransformDEModHome_gr_1605.gif]  

Remark.  The details for the partial fraction expansion are at the bottom of the page.

Therefore,  

                    [Graphics:../Images/ZTransformDEModHome_gr_1606.gif].  

We are done.   

Alternative Solution Using Tables.   Using ordinary partial fractions and Table 9.1  

and   
[Graphics:../Images/ZTransformDEModHome_gr_1607.gif]   and   [Graphics:../Images/ZTransformDEModHome_gr_1608.gif]   we get:  

                    [Graphics:../Images/ZTransformDEModHome_gr_1609.gif]  

        Since   [Graphics:../Images/ZTransformDEModHome_gr_1610.gif] and   [Graphics:../Images/ZTransformDEModHome_gr_1611.gif]we can write  

                    [Graphics:../Images/ZTransformDEModHome_gr_1612.gif]   and   

                    [Graphics:../Images/ZTransformDEModHome_gr_1613.gif]   for   [Graphics:../Images/ZTransformDEModHome_gr_1614.gif].  

Therefore, the solution has the following form:

                    [Graphics:../Images/ZTransformDEModHome_gr_1615.gif]   

We are done.   

Aside.  The commands for the ordinary partial fraction expansion are:  

[Graphics:../Images/ZTransformDEModHome_gr_1616.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1617.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1618.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1619.gif]

        Here   [Graphics:../Images/ZTransformDEModHome_gr_1620.gif]   and   [Graphics:../Images/ZTransformDEModHome_gr_1621.gif],   and we can corroborate this solution.

 

[Graphics:../Images/ZTransformDEModHome_gr_1622.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1623.gif]
[Graphics:../Images/ZTransformDEModHome_gr_1624.gif]

We are really done.   

Using Residues.   Calculate the residues  [Graphics:../Images/ZTransformDEModHome_gr_1625.gif]  at the poles   [Graphics:../Images/ZTransformDEModHome_gr_1626.gif].    

                    [Graphics:../Images/ZTransformDEModHome_gr_1627.gif]  

                    and

                    [Graphics:../Images/ZTransformDEModHome_gr_1628.gif][Graphics:../Images/ZTransformDEModHome_gr_1629.gif]  

Thus,  

                    [Graphics:../Images/ZTransformDEModHome_gr_1630.gif]   

Therefore,  

                    [Graphics:../Images/ZTransformDEModHome_gr_1631.gif]

We are really really done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ZTransformDEModHome_gr_1632.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1633.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1634.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1635.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1636.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1637.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1638.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1639.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1640.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1641.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1642.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1643.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1644.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1645.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1646.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1647.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1648.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1649.gif]

Aside.  The Maple commands are similar  

[Graphics:../Images/ZTransformDEModHome_gr_1650.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1651.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1652.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1653.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1654.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1655.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1656.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1657.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1658.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1659.gif]

We are really really really done.   

Aside.  We can use Mathematica's Rsolve subroutine.

[Graphics:../Images/ZTransformDEModHome_gr_1660.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1661.gif]

Aside.  The Maple command is similar  

[Graphics:../Images/ZTransformDEModHome_gr_1662.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1663.gif]

We are really really really really done.   

 

Aside.  We can graph some of the terms in the sequence.

 

          [Graphics:../Images/ZTransformDEModHome_gr_1664.gif]     [Graphics:../Images/ZTransformDEModHome_gr_1665.gif]     [Graphics:../Images/ZTransformDEModHome_gr_1666.gif]

                    The sequence   [Graphics:../Images/ZTransformDEModHome_gr_1667.gif].  

 

We are really really really really really done.   

The Details for the Partial Fractions.   

Aside.  How can we expand   [Graphics:../Images/ZTransformDEModHome_gr_1668.gif]   into the proper partial fractions?

It is natural to use the standard partial fraction expansion and the command:

[Graphics:../Images/ZTransformDEModHome_gr_1669.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1670.gif]

However, as we have seen, this will produce a solution involving the  [Graphics:../Images/ZTransformDEModHome_gr_1671.gif]  functions.   

This can be overcome if we use a special partial fraction expansion that is easier to use with Table 9.1.

Method (i).   Use the following algebra steps  

                    [Graphics:../Images/ZTransformDEModHome_gr_1672.gif]  

Method (ii).   Find the linear combination of   [Graphics:../Images/ZTransformDEModHome_gr_1673.gif],  

                    [Graphics:../Images/ZTransformDEModHome_gr_1674.gif].  

Equate the numerators   [Graphics:../Images/ZTransformDEModHome_gr_1675.gif],  

and solve the linear system  

                    [Graphics:../Images/ZTransformDEModHome_gr_1676.gif]  

and get   [Graphics:../Images/ZTransformDEModHome_gr_1677.gif].   

Therefore, the desired partial fraction form is  

                    [Graphics:../Images/ZTransformDEModHome_gr_1678.gif].  



Aside.   The Mathematica commands for Method (ii)  are

[Graphics:../Images/ZTransformDEModHome_gr_1683.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1684.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1685.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1686.gif]

Method (iii).   The substitution   [Graphics:../Images/ZTransformDEModHome_gr_1687.gif]   does not apply when there are multiple roots.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell