Exercise 8 (a).  Solve   [Graphics:Images/ZTransformDEModHome_gr_1767.gif]   with   [Graphics:Images/ZTransformDEModHome_gr_1768.gif].   
                          Hint.  Get  [Graphics:Images/ZTransformDEModHome_gr_1769.gif].  

Solution 8 (a).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ZTransformDEModHome_gr_1773.gif].  

Remark.   The preferred method to use involves Z-transforms, limits and residues.  

Solution.   Take the z-transform of both sides and use the initial conditions   [Graphics:../Images/ZTransformDEModHome_gr_1774.gif]:  

                    [Graphics:../Images/ZTransformDEModHome_gr_1775.gif],  

and then get    

                    [Graphics:../Images/ZTransformDEModHome_gr_1776.gif].  

New solve for  [Graphics:../Images/ZTransformDEModHome_gr_1777.gif]  and obtain:    

                    [Graphics:../Images/ZTransformDEModHome_gr_1778.gif].  

Using Tables.   Using Table 9.1 and the formula   [Graphics:../Images/ZTransformDEModHome_gr_1779.gif]   we get:  

                    [Graphics:../Images/ZTransformDEModHome_gr_1780.gif]  

Remark.  The details for the partial fraction expansion are at the bottom of the page.

Therefore,  

                    [Graphics:../Images/ZTransformDEModHome_gr_1781.gif].  

We are done.   

Alternative Solution Using Tables.   Using ordinary partial fractions and Table 9.1  

and the formula   
[Graphics:../Images/ZTransformDEModHome_gr_1782.gif]   we get:  

                    [Graphics:../Images/ZTransformDEModHome_gr_1783.gif]  

        Since   [Graphics:../Images/ZTransformDEModHome_gr_1784.gif] and   [Graphics:../Images/ZTransformDEModHome_gr_1785.gif]we can write  

                    [Graphics:../Images/ZTransformDEModHome_gr_1786.gif]   and   

                    [Graphics:../Images/ZTransformDEModHome_gr_1787.gif]   for   [Graphics:../Images/ZTransformDEModHome_gr_1788.gif].  

Therefore, the solution has the following form:

                    [Graphics:../Images/ZTransformDEModHome_gr_1789.gif]   

We are done.   

Aside.  The commands for the ordinary partial fraction expansion are:  

[Graphics:../Images/ZTransformDEModHome_gr_1790.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1791.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1792.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1793.gif]

        Here   [Graphics:../Images/ZTransformDEModHome_gr_1794.gif]   and   [Graphics:../Images/ZTransformDEModHome_gr_1795.gif],   and we can corroborate this solution.

 

[Graphics:../Images/ZTransformDEModHome_gr_1796.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1797.gif]
[Graphics:../Images/ZTransformDEModHome_gr_1798.gif]

We are really done.   

Using Residues.   Calculate residues of  [Graphics:../Images/ZTransformDEModHome_gr_1799.gif]  at the poles   [Graphics:../Images/ZTransformDEModHome_gr_1800.gif].  

                    [Graphics:../Images/ZTransformDEModHome_gr_1801.gif]  

                    and

                    [Graphics:../Images/ZTransformDEModHome_gr_1802.gif]  

Thus,  

                    [Graphics:../Images/ZTransformDEModHome_gr_1803.gif]  

Therefore,  

                    [Graphics:../Images/ZTransformDEModHome_gr_1804.gif]  

We are really really done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ZTransformDEModHome_gr_1805.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1806.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1807.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1808.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1809.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1810.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1811.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1812.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1813.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1814.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1815.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1816.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1817.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1818.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1819.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1820.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1821.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1822.gif]

Aside.  The Maple commands are similar  

[Graphics:../Images/ZTransformDEModHome_gr_1823.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1824.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1825.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1826.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1827.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1828.gif]
                                                                  
                                                            
[Graphics:../Images/ZTransformDEModHome_gr_1829.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1830.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1831.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1832.gif]

We are really really really done.   

Aside.  We can use Mathematica's Rsolve subroutine.

[Graphics:../Images/ZTransformDEModHome_gr_1833.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1834.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1835.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1836.gif]

Aside.  The Maple command is similar  

[Graphics:../Images/ZTransformDEModHome_gr_1837.gif]  

                                                            [Graphics:../Images/ZTransformDEModHome_gr_1838.gif]

We are really really really really done.   

 

Aside.  We can graph some of the terms in the sequence.

 

          [Graphics:../Images/ZTransformDEModHome_gr_1839.gif]     [Graphics:../Images/ZTransformDEModHome_gr_1840.gif]     [Graphics:../Images/ZTransformDEModHome_gr_1841.gif]

  

          [Graphics:../Images/ZTransformDEModHome_gr_1842.gif]     [Graphics:../Images/ZTransformDEModHome_gr_1843.gif]     [Graphics:../Images/ZTransformDEModHome_gr_1844.gif]

                    The sequence   [Graphics:../Images/ZTransformDEModHome_gr_1845.gif].  

 

We are really really really really really done.   

The Details for the Partial Fractions.   

Aside.  How can we expand   [Graphics:../Images/ZTransformDEModHome_gr_1846.gif]   into the proper partial fractions?

It is natural to use the standard partial fraction expansion and the command:

[Graphics:../Images/ZTransformDEModHome_gr_1847.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1848.gif]

However, as we have seen, this will produce a solution involving the  [Graphics:../Images/ZTransformDEModHome_gr_1849.gif]  functions.   

This can be overcome if we use a special partial fraction expansion that is easier to use with Table 9.1.

Method (i).   Use the following algebra steps  

                    [Graphics:../Images/ZTransformDEModHome_gr_1850.gif]  

Method (ii).   Find the linear combination of   [Graphics:../Images/ZTransformDEModHome_gr_1851.gif],  

                    [Graphics:../Images/ZTransformDEModHome_gr_1852.gif].  

Equate the numerators   [Graphics:../Images/ZTransformDEModHome_gr_1853.gif],  

and solve the linear system  

                    [Graphics:../Images/ZTransformDEModHome_gr_1854.gif]

and get   [Graphics:../Images/ZTransformDEModHome_gr_1855.gif].   

Therefore, the desired partial fraction form is  

                    [Graphics:../Images/ZTransformDEModHome_gr_1856.gif].  

Aside.   The Mathematica commands for Method (ii)  are

[Graphics:../Images/ZTransformDEModHome_gr_1857.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1858.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1859.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1860.gif]

Method (iii).  (For distinct real roots)   First make the substitution   [Graphics:../Images/ZTransformDEModHome_gr_1861.gif]   in   [Graphics:../Images/ZTransformDEModHome_gr_1862.gif]   and get  

                    [Graphics:../Images/ZTransformDEModHome_gr_1863.gif].  

Then use the standard procedure for expanding in partial fractions   

                    [Graphics:../Images/ZTransformDEModHome_gr_1864.gif].  

Then make the substitution   [Graphics:../Images/ZTransformDEModHome_gr_1865.gif]   in   [Graphics:../Images/ZTransformDEModHome_gr_1866.gif]   and get  

                    [Graphics:../Images/ZTransformDEModHome_gr_1867.gif]  

Therefore, the desired partial fraction form is  

                    [Graphics:../Images/ZTransformDEModHome_gr_1868.gif].  

Aside.   The Mathematica commands for Method (iii)  are

[Graphics:../Images/ZTransformDEModHome_gr_1869.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1870.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1871.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1872.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1873.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1874.gif]


[Graphics:../Images/ZTransformDEModHome_gr_1875.gif]

[Graphics:../Images/ZTransformDEModHome_gr_1876.gif]

Use the substitutions  

                    [Graphics:../Images/ZTransformDEModHome_gr_1877.gif],    

                    and

                    [Graphics:../Images/ZTransformDEModHome_gr_1878.gif].  

Now we have the desired partial fraction form:

                    [Graphics:../Images/ZTransformDEModHome_gr_1879.gif].  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell