Exercise 16
(a). Construct a filter using the zeros
for
attenuating signals near
.
Solution 16 (a).
See text and/or instructor's solution manual.
Answer. Compute
the product
.
The desired filter is
.
Solution. Use
the conjugate pair of zeros
and
,
and the "attenuating
factors"
and
.
Then calculate
This is a basic filter and we can use Property
(ii) Attenuating
Factors.
The transfer function for part (a) is known to have the
form
and corresponds to the filter
.
For this exercise,
we use
in
these equations to get the desired recursive formula
.
Therefore, the desired filter for part (a) is
.
We are done.
Aside. We can let Mathematica double check our work.
Aside. The Maple
commands are similar
We are really done.
Aside. We can graph
the amplitude response for the filter
.
![[Graphics:../Images/ZTransformFilterModHome_gr_1803.gif]](../Images/ZTransformFilterModHome_gr_1803.gif)
Amplitude
response
,
and
zero-pole plot of
,
for
the filter
.
We
can see that some of the high-range frequencies are slightly
attenuated.
We are really really done.
Aside. For
illustration, we can graph the causal input
sequence
,
and the corresponding causal output
sequence
.
The signal component
will
be amplified by the factor
, and
The signal component
will
be slightly attenuated by the factor
.
![[Graphics:../Images/ZTransformFilterModHome_gr_1820.gif]](../Images/ZTransformFilterModHome_gr_1820.gif)
The
causal input sequence
and
the corresponding causal output sequence.
Here
we have
and
.
This
filter reduces the proportion of the signal
component
by
a factor of
.
This solution is complements of the authors.
(c) 20098 John H. Mathews, Russell W. Howell