Exercise 16 (a).   Construct a filter using the zeros [Graphics:Images/ZTransformFilterModHome_gr_1770.gif]   for attenuating signals near   [Graphics:Images/ZTransformFilterModHome_gr_1771.gif].  

Solution 16 (a).

See text and/or instructor's solution manual.

Answer.   Compute the product  

                    [Graphics:../Images/ZTransformFilterModHome_gr_1777.gif].  

The desired filter is  

                    [Graphics:../Images/ZTransformFilterModHome_gr_1778.gif].  

Solution.   Use the conjugate pair of zeros   [Graphics:../Images/ZTransformFilterModHome_gr_1779.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_1780.gif],  

and the "attenuating factors"   [Graphics:../Images/ZTransformFilterModHome_gr_1781.gif]   and    [Graphics:../Images/ZTransformFilterModHome_gr_1782.gif].  

Then calculate  

                    [Graphics:../Images/ZTransformFilterModHome_gr_1783.gif]  

This is a basic filter and we can use Property (ii) Attenuating Factors.  

The transfer function for part (a) is known to have the form  

                    [Graphics:../Images/ZTransformFilterModHome_gr_1784.gif]  

and corresponds to the filter

                    [Graphics:../Images/ZTransformFilterModHome_gr_1785.gif].  

        For this exercise, we use   [Graphics:../Images/ZTransformFilterModHome_gr_1786.gif]   in these equations to get the desired recursive formula  

                    [Graphics:../Images/ZTransformFilterModHome_gr_1787.gif].  

Therefore, the desired filter for part (a) is

                    [Graphics:../Images/ZTransformFilterModHome_gr_1788.gif].  

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ZTransformFilterModHome_gr_1789.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1790.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_1791.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1792.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_1793.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1794.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_1795.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1796.gif]

Aside.  The Maple commands are similar  

[Graphics:../Images/ZTransformFilterModHome_gr_1797.gif]  

                                                            [Graphics:../Images/ZTransformFilterModHome_gr_1798.gif]  


[Graphics:../Images/ZTransformFilterModHome_gr_1799.gif]  

                                                            [Graphics:../Images/ZTransformFilterModHome_gr_1800.gif]  

 

We are really done.   

Aside.  We can graph the amplitude response for the filter   [Graphics:../Images/ZTransformFilterModHome_gr_1801.gif].  

 

                    [Graphics:../Images/ZTransformFilterModHome_gr_1802.gif]          [Graphics:../Images/ZTransformFilterModHome_gr_1803.gif]

                    Amplitude response   [Graphics:../Images/ZTransformFilterModHome_gr_1804.gif],   

                    and zero-pole plot of   [Graphics:../Images/ZTransformFilterModHome_gr_1805.gif],  

                    for the filter   [Graphics:../Images/ZTransformFilterModHome_gr_1806.gif].

                    We can see that some of the high-range frequencies are slightly attenuated.

 

We are really really done.   

Aside.  For illustration, we can graph the causal input sequence   [Graphics:../Images/ZTransformFilterModHome_gr_1807.gif],  

and the corresponding causal output sequence   [Graphics:../Images/ZTransformFilterModHome_gr_1808.gif].  

The signal component  [Graphics:../Images/ZTransformFilterModHome_gr_1809.gif]  will be amplified  by the factor  [Graphics:../Images/ZTransformFilterModHome_gr_1810.gif],  and  

The signal component  [Graphics:../Images/ZTransformFilterModHome_gr_1811.gif]  will be slightly attenuated by the factor  [Graphics:../Images/ZTransformFilterModHome_gr_1812.gif].  

[Graphics:../Images/ZTransformFilterModHome_gr_1813.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1814.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_1815.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1816.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_1817.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1818.gif]

                    [Graphics:../Images/ZTransformFilterModHome_gr_1819.gif]          [Graphics:../Images/ZTransformFilterModHome_gr_1820.gif]

                    The causal input sequence   [Graphics:../Images/ZTransformFilterModHome_gr_1821.gif]   and the corresponding causal output sequence.

                    Here we have  [Graphics:../Images/ZTransformFilterModHome_gr_1822.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_1823.gif].  
                    
                    This filter reduces the proportion of the signal component   [Graphics:../Images/ZTransformFilterModHome_gr_1824.gif]   by a factor of   [Graphics:../Images/ZTransformFilterModHome_gr_1825.gif].

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 20098 John H. Mathews, Russell W. Howell