Exercise 16 (b).   Construct a filter using the poles   [Graphics:Images/ZTransformFilterModHome_gr_1772.gif]   for boosting up signals near  [Graphics:Images/ZTransformFilterModHome_gr_1773.gif]  and  [Graphics:Images/ZTransformFilterModHome_gr_1774.gif]  and low frequency signals.  

Hint.  This is similar to Example 9.25 (b).  

Solution 16 (b).

See text and/or instructor's solution manual.

Answer.   Compute the quotient  

                    [Graphics:../Images/ZTransformFilterModHome_gr_1826.gif].  

The desired filter is  

                    [Graphics:../Images/ZTransformFilterModHome_gr_1827.gif].  

Solution.   Use the conjugate pair of poles   [Graphics:../Images/ZTransformFilterModHome_gr_1828.gif],  

and the "boost up factors"   [Graphics:../Images/ZTransformFilterModHome_gr_1829.gif].  

Then calculate

                    [Graphics:../Images/ZTransformFilterModHome_gr_1830.gif]  

Use the Boosting Up Filter and see that the transfer function

                    [Graphics:../Images/ZTransformFilterModHome_gr_1831.gif],  

will correspond to the filter

                    [Graphics:../Images/ZTransformFilterModHome_gr_1832.gif].  

        For this exercise, we use   [Graphics:../Images/ZTransformFilterModHome_gr_1833.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_1834.gif]   in these equations to get the desired recursive formula  

                    [Graphics:../Images/ZTransformFilterModHome_gr_1835.gif].  

Therefore, the desired filter for part (b) is

                    [Graphics:../Images/ZTransformFilterModHome_gr_1836.gif].  

 

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ZTransformFilterModHome_gr_1837.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1838.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_1839.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1840.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_1841.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1842.gif]

Aside.  The Maple commands are similar  

[Graphics:../Images/ZTransformFilterModHome_gr_1843.gif]  

                                                            [Graphics:../Images/ZTransformFilterModHome_gr_1844.gif]  


[Graphics:../Images/ZTransformFilterModHome_gr_1845.gif]  

                                                            [Graphics:../Images/ZTransformFilterModHome_gr_1846.gif]  

 

We are really done.   

Aside.  We can graph the amplitude response for the filter   [Graphics:../Images/ZTransformFilterModHome_gr_1847.gif].  

 

                    [Graphics:../Images/ZTransformFilterModHome_gr_1848.gif]          [Graphics:../Images/ZTransformFilterModHome_gr_1849.gif]

                    Amplitude response   [Graphics:../Images/ZTransformFilterModHome_gr_1850.gif],   

                    and zero-pole plot of   [Graphics:../Images/ZTransformFilterModHome_gr_1851.gif],  

                    for the filter   [Graphics:../Images/ZTransformFilterModHome_gr_1852.gif].

                    We can see that the low-range frequencies are slightly amplified.

 

We are really really done.   

Aside.  For illustration, we can graph the causal input sequence   [Graphics:../Images/ZTransformFilterModHome_gr_1853.gif],  

and the corresponding causal output sequence   [Graphics:../Images/ZTransformFilterModHome_gr_1854.gif].  

The signal component  [Graphics:../Images/ZTransformFilterModHome_gr_1855.gif]  will be amplified  by the factor  [Graphics:../Images/ZTransformFilterModHome_gr_1856.gif],  and  

The signal component  [Graphics:../Images/ZTransformFilterModHome_gr_1857.gif]  will be attenuated by the factor  [Graphics:../Images/ZTransformFilterModHome_gr_1858.gif].  

[Graphics:../Images/ZTransformFilterModHome_gr_1859.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1860.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_1861.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1862.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_1863.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_1864.gif]

                    [Graphics:../Images/ZTransformFilterModHome_gr_1865.gif]          [Graphics:../Images/ZTransformFilterModHome_gr_1866.gif]

                    The causal input sequence   [Graphics:../Images/ZTransformFilterModHome_gr_1867.gif]   and the corresponding causal output sequence.

                    Here we have  [Graphics:../Images/ZTransformFilterModHome_gr_1868.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_1869.gif].  
                    
                    This filter reduces the proportion of the signal component   [Graphics:../Images/ZTransformFilterModHome_gr_1870.gif]   by a factor of   [Graphics:../Images/ZTransformFilterModHome_gr_1871.gif].

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 20098 John H. Mathews, Russell W. Howell