Exercise 17 (b).   Construct a filter using the poles   [Graphics:Images/ZTransformFilterModHome_gr_1942.gif]   for boosting up signals near  [Graphics:Images/ZTransformFilterModHome_gr_1943.gif]  and  [Graphics:Images/ZTransformFilterModHome_gr_1944.gif]  and low frequency signals.  

Hint.  This is similar to Example 9.25 (b).  

Solution 17 (b).

See text and/or instructor's solution manual.

Answer.   Compute the quotient  

                    [Graphics:../Images/ZTransformFilterModHome_gr_1997.gif].  

The desired filter is  

                    [Graphics:../Images/ZTransformFilterModHome_gr_1998.gif].  

Solution.   Use the conjugate pair of poles   [Graphics:../Images/ZTransformFilterModHome_gr_1999.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_2000.gif],  

and the "boost up factors"   [Graphics:../Images/ZTransformFilterModHome_gr_2001.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_2002.gif].  

Then calculate

                    [Graphics:../Images/ZTransformFilterModHome_gr_2003.gif]  

Extending the Boosting Up Filter one more term we see that the transfer function

                    [Graphics:../Images/ZTransformFilterModHome_gr_2004.gif],  

will correspond to the filter

                    [Graphics:../Images/ZTransformFilterModHome_gr_2005.gif].  

        For this exercise, we use   [Graphics:../Images/ZTransformFilterModHome_gr_2006.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_2007.gif]   in these equations to get the desired recursive formula  

                    [Graphics:../Images/ZTransformFilterModHome_gr_2008.gif].  

Therefore, the desired filter for part (b) is

                    [Graphics:../Images/ZTransformFilterModHome_gr_2009.gif].  

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ZTransformFilterModHome_gr_2010.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2011.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2012.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2013.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2014.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2015.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2016.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2017.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2018.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2019.gif]

Aside.  The Maple commands are similar  

[Graphics:../Images/ZTransformFilterModHome_gr_2020.gif]  

                                                            [Graphics:../Images/ZTransformFilterModHome_gr_2021.gif]  


[Graphics:../Images/ZTransformFilterModHome_gr_2022.gif]  

                                                            [Graphics:../Images/ZTransformFilterModHome_gr_2023.gif]  

 

We are really done.   

Aside.  We can graph the amplitude response for the filter   [Graphics:../Images/ZTransformFilterModHome_gr_2024.gif].  

 

                    [Graphics:../Images/ZTransformFilterModHome_gr_2025.gif]          [Graphics:../Images/ZTransformFilterModHome_gr_2026.gif]

                    Amplitude response   [Graphics:../Images/ZTransformFilterModHome_gr_2027.gif],   

                    and zero-pole plot of   [Graphics:../Images/ZTransformFilterModHome_gr_2028.gif],  

                    We can see that some of the low-range frequencies are slightly amplified.

 

We are really really done.   

Aside.  For illustration, we can graph the causal input sequence   [Graphics:../Images/ZTransformFilterModHome_gr_2029.gif],  

and the corresponding causal output sequence   [Graphics:../Images/ZTransformFilterModHome_gr_2030.gif].  

The signal component  [Graphics:../Images/ZTransformFilterModHome_gr_2031.gif]  will be amplified  by the factor  [Graphics:../Images/ZTransformFilterModHome_gr_2032.gif],  and  

The signal component  [Graphics:../Images/ZTransformFilterModHome_gr_2033.gif]  will be attenuated by the factor  [Graphics:../Images/ZTransformFilterModHome_gr_2034.gif].  

[Graphics:../Images/ZTransformFilterModHome_gr_2035.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2036.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2037.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2038.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2039.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2040.gif]

                    [Graphics:../Images/ZTransformFilterModHome_gr_2041.gif]          [Graphics:../Images/ZTransformFilterModHome_gr_2042.gif]

                    The causal input sequence   [Graphics:../Images/ZTransformFilterModHome_gr_2043.gif]   and the corresponding causal output sequence.

                    Here we have  [Graphics:../Images/ZTransformFilterModHome_gr_2044.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_2045.gif]
                    
                    This filter reduces the proportion of the signal component   [Graphics:../Images/ZTransformFilterModHome_gr_2046.gif]   by a factor of   [Graphics:../Images/ZTransformFilterModHome_gr_2047.gif].

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 20098 John H. Mathews, Russell W. Howell