Exercise 18 (b).   Construct a filter using the poles   [Graphics:Images/ZTransformFilterModHome_gr_2109.gif]   for boosting up signals near  [Graphics:Images/ZTransformFilterModHome_gr_2110.gif]  and  [Graphics:Images/ZTransformFilterModHome_gr_2111.gif].

Solution 18 (b).

See text and/or instructor's solution manual.

Answer.   Compute the quotient  

                    [Graphics:../Images/ZTransformFilterModHome_gr_2167.gif].  

The desired filter is  

                    [Graphics:../Images/ZTransformFilterModHome_gr_2168.gif].  

Solution.   Use the conjugate pair of poles   [Graphics:../Images/ZTransformFilterModHome_gr_2169.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_2170.gif],  

and the "boost up factors"   [Graphics:../Images/ZTransformFilterModHome_gr_2171.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_2172.gif].  

Then calculate  

                    [Graphics:../Images/ZTransformFilterModHome_gr_2173.gif]

Extending the Boosting Up Filter one more term we see that the transfer function

                    [Graphics:../Images/ZTransformFilterModHome_gr_2174.gif]

will correspond to the filter

                    [Graphics:../Images/ZTransformFilterModHome_gr_2175.gif].  

        For this exercise, we use   [Graphics:../Images/ZTransformFilterModHome_gr_2176.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_2177.gif]   in these equations to get the desired recursive formula  

                    [Graphics:../Images/ZTransformFilterModHome_gr_2178.gif].  

Therefore, the desired filter for part (b) is

                    [Graphics:../Images/ZTransformFilterModHome_gr_2179.gif].  

 

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ZTransformFilterModHome_gr_2180.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2181.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2182.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2183.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2184.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2185.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2186.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2187.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2188.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2189.gif]

Aside.  The Maple commands are similar  

[Graphics:../Images/ZTransformFilterModHome_gr_2190.gif]  

                                                            [Graphics:../Images/ZTransformFilterModHome_gr_2191.gif]  


[Graphics:../Images/ZTransformFilterModHome_gr_2192.gif]  

                                                            [Graphics:../Images/ZTransformFilterModHome_gr_2193.gif]  

 

We are really done.   

Aside.  We can graph the amplitude response for the filter   [Graphics:../Images/ZTransformFilterModHome_gr_2194.gif].

  

                    [Graphics:../Images/ZTransformFilterModHome_gr_2195.gif]          [Graphics:../Images/ZTransformFilterModHome_gr_2196.gif]

                    Amplitude response   [Graphics:../Images/ZTransformFilterModHome_gr_2197.gif],   

                    and zero-pole plot of   [Graphics:../Images/ZTransformFilterModHome_gr_2198.gif],  

                    for the filter   [Graphics:../Images/ZTransformFilterModHome_gr_2199.gif].

                    We can see that a few of the mid-range frequencies are slightly amplified.

 

We are really really done.   

Aside.  For illustration, we can graph the causal input sequence   [Graphics:../Images/ZTransformFilterModHome_gr_2200.gif],  

and the corresponding causal output sequence   [Graphics:../Images/ZTransformFilterModHome_gr_2201.gif].  

The signal component  [Graphics:../Images/ZTransformFilterModHome_gr_2202.gif]  will be amplified  by the factor  [Graphics:../Images/ZTransformFilterModHome_gr_2203.gif],  and  

The signal component  [Graphics:../Images/ZTransformFilterModHome_gr_2204.gif]  will be attenuated by the factor  [Graphics:../Images/ZTransformFilterModHome_gr_2205.gif].  

[Graphics:../Images/ZTransformFilterModHome_gr_2206.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2207.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2208.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2209.gif]


[Graphics:../Images/ZTransformFilterModHome_gr_2210.gif]

[Graphics:../Images/ZTransformFilterModHome_gr_2211.gif]

                    [Graphics:../Images/ZTransformFilterModHome_gr_2212.gif]          [Graphics:../Images/ZTransformFilterModHome_gr_2213.gif]

                    The causal input sequence   [Graphics:../Images/ZTransformFilterModHome_gr_2214.gif]   and the corresponding causal output sequence.

                    Here we have  [Graphics:../Images/ZTransformFilterModHome_gr_2215.gif]   and   [Graphics:../Images/ZTransformFilterModHome_gr_2216.gif]
                    
                    This filter reduces the proportion of the signal component   [Graphics:../Images/ZTransformFilterModHome_gr_2217.gif]   by a factor of   [Graphics:../Images/ZTransformFilterModHome_gr_2218.gif].

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 20098 John H. Mathews, Russell W. Howell