Exercise 8. Find
using
two methods. (i) Partial fractions and
Table
9.1. (ii)
Using residues.
8 (a).
. Hint.
.
Solution 8 (a).
See text and/or instructor's solution manual.
Answer.
.
Solution (i). Using
Table
9.1 of z-transforms we
get
Remark. The details for the partial fraction expansion are at the bottom of the page.
We are done.
Solution (ii). Using
residues we get
and
Hence,
Therefore,
.
We are done.
Aside. We can let Mathematica double check our work.
The
Maple code is similar
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The
Maple code using limits is similar
![]()
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The
Maple code using residues is similar
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We are really done.
Aside. We can graph some of the terms in the sequence.
![[Graphics:../Images/ZTransformIntroModHome_gr_270.gif]](../Images/ZTransformIntroModHome_gr_270.gif)
The
sequence
.
We are really really done.
The Details for the Partial Fractions.
Aside. How can we
expand
into
the proper partial fractions?
It is natural to try the command:
But this is not the desired form for using Table 9.1 of z-transforms.
Method
(i). Use the following algebra
steps
Method
(ii). Find the linear combination
of
,
.
Equate the numerators
,
and solve the linear system
![[Graphics:../Images/ZTransformIntroModHome_gr_279.gif]](../Images/ZTransformIntroModHome_gr_279.gif)
and get
.
Therefore, the desired form is
.
Aside. The Mathematica commands for Method (ii) are
Method
(iii). (For distinct
real roots) First make the
substitution
in
and
get
.
Then use the standard procedure for expanding in partial
fractions
.
Then make the substitution
in
and
get
Therefore, the desired form is
.
Aside. The Mathematica commands for Method (iii) are
Now we have the desired form:
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell