Exercise 8.  Find   [Graphics:Images/ZTransformIntroModHome_gr_223.gif]  using two methods.   (i) Partial fractions and Table 9.1.   (ii) Using residues.  

8 (b).  [Graphics:Images/ZTransformIntroModHome_gr_226.gif].     Hint.  [Graphics:Images/ZTransformIntroModHome_gr_227.gif].  

Solution 8 (b).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ZTransformIntroModHome_gr_303.gif].  

Solution (i).   Using Table 9.1 of z-transforms we get

                    [Graphics:../Images/ZTransformIntroModHome_gr_304.gif]  

Remark.  The details for the partial fraction expansion are at the bottom of the page.

 

We are done.   

 

 

Solution (ii).   Using residues we get

                    [Graphics:../Images/ZTransformIntroModHome_gr_305.gif]  

Therefore,

                    [Graphics:../Images/ZTransformIntroModHome_gr_306.gif].  

 

We are done.   

Aside.  We can let Mathematica double check our work.

 

[Graphics:../Images/ZTransformIntroModHome_gr_307.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_308.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_309.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_310.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_311.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_312.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_313.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_314.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_315.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_316.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_317.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_318.gif]

          The Maple code is similar

[Graphics:../Images/ZTransformIntroModHome_gr_319.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_320.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_321.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_322.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_323.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_324.gif]

          The Maple code using limits is similar

[Graphics:../Images/ZTransformIntroModHome_gr_325.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_326.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_327.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_328.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_329.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_330.gif]

          The Maple code using residues is similar

[Graphics:../Images/ZTransformIntroModHome_gr_331.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_332.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_333.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_334.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_335.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_336.gif]

 

We are really done.   

Aside.  We can graph some of the terms in the sequence.

 

          [Graphics:../Images/ZTransformIntroModHome_gr_337.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_338.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_339.gif]

                                                                                                                        The sequence   [Graphics:../Images/ZTransformIntroModHome_gr_340.gif].   

 

 

We are really really done.   

The Details for the Partial Fractions.   

Aside.  How can we expand   [Graphics:../Images/ZTransformIntroModHome_gr_341.gif]   into the proper partial fractions?

It is natural to try the command:

[Graphics:../Images/ZTransformIntroModHome_gr_342.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_343.gif]

But this is not the desired form for using Table 9.1 of z-transforms.

 

Method (i).   Use the following algebra steps  

                    [Graphics:../Images/ZTransformIntroModHome_gr_344.gif]  

Now we have the desired form:

                    [Graphics:../Images/ZTransformIntroModHome_gr_345.gif].  

Method (ii).   Find the linear combination of   [Graphics:../Images/ZTransformIntroModHome_gr_346.gif],  

                    [Graphics:../Images/ZTransformIntroModHome_gr_347.gif].  

Equate the numerators   [Graphics:../Images/ZTransformIntroModHome_gr_348.gif],  

and solve the linear system  

                    [Graphics:../Images/ZTransformIntroModHome_gr_349.gif]

and get   [Graphics:../Images/ZTransformIntroModHome_gr_350.gif].   

Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_351.gif].  

Aside.   The Mathematica commands for Method (ii)  are

[Graphics:../Images/ZTransformIntroModHome_gr_352.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_353.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_354.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_355.gif]

Method (iii).   The substitution   [Graphics:../Images/ZTransformIntroModHome_gr_356.gif]   does not apply when there are multiple roots.

 

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell