Exercise 8.  Find   [Graphics:Images/ZTransformIntroModHome_gr_223.gif]  using two methods.   (i) Partial fractions and Table 9.1.   (ii) Using residues.  

8 (c).  [Graphics:Images/ZTransformIntroModHome_gr_228.gif].           Hint.  [Graphics:Images/ZTransformIntroModHome_gr_229.gif].  

Solution 8 (c).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ZTransformIntroModHome_gr_357.gif].  

Solution (i).   Using Table 9.1 of z-transforms we get

                    [Graphics:../Images/ZTransformIntroModHome_gr_358.gif]  

Remark.  The details for the partial fraction expansion are at the bottom of the page.

 

We are done.   

 

 

Solution (ii).   Using residues we get

                    [Graphics:../Images/ZTransformIntroModHome_gr_359.gif]  

                    and

                    [Graphics:../Images/ZTransformIntroModHome_gr_360.gif]  

Hence,  

                    [Graphics:../Images/ZTransformIntroModHome_gr_361.gif]  

Therefore,

                    [Graphics:../Images/ZTransformIntroModHome_gr_362.gif].  

Aside.  The solution can be put into the form

                    [Graphics:../Images/ZTransformIntroModHome_gr_363.gif]  

Therefore,

                    [Graphics:../Images/ZTransformIntroModHome_gr_364.gif].  

 

We are done.   

Aside.  We can let Mathematica double check our work.

 

[Graphics:../Images/ZTransformIntroModHome_gr_365.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_366.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_367.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_368.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_369.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_370.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_371.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_372.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_373.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_374.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_375.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_376.gif]

          The Maple code is similar

[Graphics:../Images/ZTransformIntroModHome_gr_377.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_378.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_379.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_380.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_381.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_382.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_383.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_384.gif]

          The Maple code using limits is similar

[Graphics:../Images/ZTransformIntroModHome_gr_385.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_386.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_387.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_388.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_389.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_390.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_391.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_392.gif]

          The Maple code using residues is similar

[Graphics:../Images/ZTransformIntroModHome_gr_393.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_394.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_395.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_396.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_397.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_398.gif]

 

We are really done.   

Aside.  We can graph some of the terms in the sequence.

 

          [Graphics:../Images/ZTransformIntroModHome_gr_399.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_400.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_401.gif]

                                                                                                                        The sequence   [Graphics:../Images/ZTransformIntroModHome_gr_402.gif].  

 

 

We are really really done.   

The Details for the Partial Fractions.   

Aside.  How can we expand   [Graphics:../Images/ZTransformIntroModHome_gr_403.gif]   into the proper partial fractions?

It is natural to try the command:

[Graphics:../Images/ZTransformIntroModHome_gr_404.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_405.gif]

But this is not the desired form for using Table 9.1 of z-transforms.

 

Method (i).   Use the following algebra steps  

                    [Graphics:../Images/ZTransformIntroModHome_gr_406.gif]  

Now we have the desired form:

                    [Graphics:../Images/ZTransformIntroModHome_gr_407.gif].

Method (ii).   Find the linear combination of   [Graphics:../Images/ZTransformIntroModHome_gr_408.gif],  

                    [Graphics:../Images/ZTransformIntroModHome_gr_409.gif].  

Equate the numerators   [Graphics:../Images/ZTransformIntroModHome_gr_410.gif],  

and solve the linear system  

                    [Graphics:../Images/ZTransformIntroModHome_gr_411.gif]  

and get   [Graphics:../Images/ZTransformIntroModHome_gr_412.gif].   

Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_413.gif].  

Aside.   The Mathematica commands for Method (ii)  are

[Graphics:../Images/ZTransformIntroModHome_gr_414.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_415.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_416.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_417.gif]

Method (iii).   The substitution   [Graphics:../Images/ZTransformIntroModHome_gr_418.gif]   does not apply when there are complex roots.

 

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell