Exercise 9.  Use residues to find   [Graphics:Images/ZTransformIntroModHome_gr_419.gif].  

9 (b).  [Graphics:Images/ZTransformIntroModHome_gr_421.gif].     Hint.  [Graphics:Images/ZTransformIntroModHome_gr_422.gif].  

Solution 9 (b).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ZTransformIntroModHome_gr_447.gif].  

Aside.   We could use Table 9.1 of z-transforms and get the solution  

                    
[Graphics:../Images/ZTransformIntroModHome_gr_448.gif]  

Remark.  The details for the partial fraction expansion are at the bottom of the page.

 

Solution.   Using residues we get

                    [Graphics:../Images/ZTransformIntroModHome_gr_449.gif]  
                    
                    and

                    [Graphics:../Images/ZTransformIntroModHome_gr_450.gif]  

Thus,  

                    [Graphics:../Images/ZTransformIntroModHome_gr_451.gif]  

Therefore,

                    [Graphics:../Images/ZTransformIntroModHome_gr_452.gif].  

 

We are done.   

Aside.  We can let Mathematica double check our work.

 

[Graphics:../Images/ZTransformIntroModHome_gr_453.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_454.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_455.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_456.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_457.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_458.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_461.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_462.gif]

Aside.  We can use Mathematica's  Limit  and  Residue  subroutines.

[Graphics:../Images/ZTransformIntroModHome_gr_463.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_464.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_465.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_466.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_467.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_468.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_469.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_470.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_471.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_472.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_473.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_474.gif]

          The Maple code using limits is similar  

[Graphics:../Images/ZTransformIntroModHome_gr_475.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_476.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_477.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_478.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_479.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_480.gif]

          The Maple code using residues is similar  

[Graphics:../Images/ZTransformIntroModHome_gr_481.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_482.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_483.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_484.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_485.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_486.gif]

          We can use Maple's subroutine to find the inverse.  

[Graphics:../Images/ZTransformIntroModHome_gr_487.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_488.gif]

 

We are really done.   

Aside.  We can graph some of the terms in the sequence.

 

          [Graphics:../Images/ZTransformIntroModHome_gr_489.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_490.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_491.gif]

                                                                                                                        The sequence   [Graphics:../Images/ZTransformIntroModHome_gr_492.gif].  

 

 

We are really really done.   

The Details for the Partial Fractions.   

Aside.   How can we expand   [Graphics:../Images/ZTransformIntroModHome_gr_493.gif]   into the proper partial fractions?

It is natural to try the command:

[Graphics:../Images/ZTransformIntroModHome_gr_494.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_495.gif]

But this is not the desired form for using Table 9.1 of z-transforms.

 

Method (i).   Use the following algebra steps  

                    [Graphics:../Images/ZTransformIntroModHome_gr_496.gif]  

Method (ii).   Find the linear combination of   [Graphics:../Images/ZTransformIntroModHome_gr_497.gif]  

                    [Graphics:../Images/ZTransformIntroModHome_gr_498.gif].  

Equate the numerators   [Graphics:../Images/ZTransformIntroModHome_gr_499.gif],  

and solve the linear system  

                    [Graphics:../Images/ZTransformIntroModHome_gr_500.gif]

and get   [Graphics:../Images/ZTransformIntroModHome_gr_501.gif].   

Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_502.gif]

Aside.   The Mathematica commands for Method (ii)  are

[Graphics:../Images/ZTransformIntroModHome_gr_503.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_504.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_505.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_506.gif]

Method (iii).  (For distinct real roots)   First make the substitution   [Graphics:../Images/ZTransformIntroModHome_gr_507.gif]   in   [Graphics:../Images/ZTransformIntroModHome_gr_508.gif]   and get  

                    [Graphics:../Images/ZTransformIntroModHome_gr_509.gif].  

Then use the standard procedure for expanding in partial fractions   

                    [Graphics:../Images/ZTransformIntroModHome_gr_510.gif].  

Then make the substitution   [Graphics:../Images/ZTransformIntroModHome_gr_511.gif]   in   [Graphics:../Images/ZTransformIntroModHome_gr_512.gif]   and get  

                    [Graphics:../Images/ZTransformIntroModHome_gr_513.gif]  

Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_514.gif].  

Aside.   The Mathematica commands for Method (iii)  are

[Graphics:../Images/ZTransformIntroModHome_gr_515.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_516.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_517.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_518.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_519.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_520.gif]

Now use the substitutions  

                    [Graphics:../Images/ZTransformIntroModHome_gr_521.gif],    

                    and  
                    
                    [Graphics:../Images/ZTransformIntroModHome_gr_522.gif].  
                    
Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_523.gif].  

 

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell