Exercise 9.  Use residues to find   [Graphics:Images/ZTransformIntroModHome_gr_419.gif].  

9 (c).  [Graphics:Images/ZTransformIntroModHome_gr_423.gif].              Hint.   [Graphics:Images/ZTransformIntroModHome_gr_424.gif].  

Solution 9 (c).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ZTransformIntroModHome_gr_524.gif].  

Aside.   We could use Table 9.1 of z-transforms and get the solution  

                    
[Graphics:../Images/ZTransformIntroModHome_gr_525.gif]  

Remark.  The details for the partial fraction expansion are at the bottom of the page.

 

Solution.   Using residues we get

                    [Graphics:../Images/ZTransformIntroModHome_gr_526.gif]  
                    
                    and

                    [Graphics:../Images/ZTransformIntroModHome_gr_527.gif]  

Thus,  

                    [Graphics:../Images/ZTransformIntroModHome_gr_528.gif]  

Therefore,

                    [Graphics:../Images/ZTransformIntroModHome_gr_529.gif].  

 

We are done.   

Aside.  We can let Mathematica double check our work.

 

[Graphics:../Images/ZTransformIntroModHome_gr_530.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_531.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_532.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_533.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_534.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_535.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_536.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_537.gif]

Aside.  We can use Mathematica's  Limit  and  Residue  subroutines.

[Graphics:../Images/ZTransformIntroModHome_gr_538.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_539.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_540.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_541.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_542.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_543.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_544.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_545.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_546.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_547.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_548.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_549.gif]

          The Maple code using limits is similar  

[Graphics:../Images/ZTransformIntroModHome_gr_550.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_551.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_552.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_553.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_554.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_555.gif]

          The Maple code using residues is similar  

[Graphics:../Images/ZTransformIntroModHome_gr_556.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_557.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_558.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_559.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_560.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_561.gif]

          We can use Maple's subroutine to find the inverse.  

[Graphics:../Images/ZTransformIntroModHome_gr_562.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_563.gif]

 

We are really done.   

Aside.  We can graph some of the terms in the sequence.

 

          [Graphics:../Images/ZTransformIntroModHome_gr_564.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_565.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_566.gif]

                                                                                                                        The sequence   [Graphics:../Images/ZTransformIntroModHome_gr_567.gif].  

 

 

We are really really done.   

The Details for the Partial Fractions.   

Aside.   How can we expand   [Graphics:../Images/ZTransformIntroModHome_gr_568.gif]   into the proper partial fractions?

It is natural to try the command:

[Graphics:../Images/ZTransformIntroModHome_gr_569.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_570.gif]

But this is not the desired form for using Table 9.1 of z-transforms.

 

Method (i).   Use the following algebra steps  

                    [Graphics:../Images/ZTransformIntroModHome_gr_571.gif]  

Method (ii).   Find the linear combination of   [Graphics:../Images/ZTransformIntroModHome_gr_572.gif]  

                    [Graphics:../Images/ZTransformIntroModHome_gr_573.gif].  

Equate the numerators   [Graphics:../Images/ZTransformIntroModHome_gr_574.gif],  

and solve the linear system  

                    [Graphics:../Images/ZTransformIntroModHome_gr_575.gif]

and get   [Graphics:../Images/ZTransformIntroModHome_gr_576.gif].   

Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_577.gif]

Aside.   The Mathematica commands for Method (ii)  are

[Graphics:../Images/ZTransformIntroModHome_gr_578.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_579.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_580.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_581.gif]

Method (iii).  (For distinct real roots)   First make the substitution   [Graphics:../Images/ZTransformIntroModHome_gr_582.gif]   in   [Graphics:../Images/ZTransformIntroModHome_gr_583.gif]   and get  

                    [Graphics:../Images/ZTransformIntroModHome_gr_584.gif].  

Then use the standard procedure for expanding in partial fractions   

                    [Graphics:../Images/ZTransformIntroModHome_gr_585.gif].  

Then make the substitution   [Graphics:../Images/ZTransformIntroModHome_gr_586.gif]   in   [Graphics:../Images/ZTransformIntroModHome_gr_587.gif]   and get  

                    [Graphics:../Images/ZTransformIntroModHome_gr_588.gif]  

Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_589.gif].  

Aside.   The Mathematica commands for Method (iii)  are

[Graphics:../Images/ZTransformIntroModHome_gr_590.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_591.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_592.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_593.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_594.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_595.gif]

Now use the substitutions  

                    [Graphics:../Images/ZTransformIntroModHome_gr_596.gif],    

                    and  
                    
                    [Graphics:../Images/ZTransformIntroModHome_gr_597.gif].  
                    
Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_598.gif].  

 

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell