Exercise 1.  Use the definition of the z-transform to find   [Graphics:Images/ZTransformIntroModHome_gr_1.gif].

1 (c).  For the sequence   [Graphics:Images/ZTransformIntroModHome_gr_4.gif].  

Solution 1 (c).

See text and/or instructor's solution manual.

Answer.   .  

Solution.   Use Definition 9.1 and obtain   

                    
[Graphics:../Images/ZTransformIntroModHome_gr_36.gif]  

Therefore,   

                    .  

 

We are done.   

Aside.  We can let Mathematica double check our work.

 

[Graphics:../Images/ZTransformIntroModHome_gr_38.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_39.gif]

          The Maple code is similar

[Graphics:../Images/ZTransformIntroModHome_gr_40.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_41.gif]

 

Aside.  We can use Mathematica's ZTransform subroutine.

 

[Graphics:../Images/ZTransformIntroModHome_gr_42.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_43.gif]

          The Maple code is similar

[Graphics:../Images/ZTransformIntroModHome_gr_44.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_45.gif]

 

We are really done.   

Aside.  We can graph some of the terms in the sequence.

 

          [Graphics:../Images/ZTransformIntroModHome_gr_46.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_47.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_48.gif]

                                                                                                                        The sequence   [Graphics:../Images/ZTransformIntroModHome_gr_49.gif].   

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell