Exercise 17.  In the Newton law of heating and cooling model  [Graphics:Images/ZTransformIntroModHome_gr_1156.gif]  

use the parameters   [Graphics:Images/ZTransformIntroModHome_gr_1157.gif]   and initial condition   [Graphics:Images/ZTransformIntroModHome_gr_1158.gif].

17 (a).  Use the z-transform and tables to find the solution.    Hint.   Get  [Graphics:Images/ZTransformIntroModHome_gr_1159.gif]

17 (b).  Use residues to find the solution.

Solution 17.

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ZTransformIntroModHome_gr_1160.gif].  

Solution 17 (a).

        Substitute   [Graphics:../Images/ZTransformIntroModHome_gr_1161.gif]   into   [Graphics:../Images/ZTransformIntroModHome_gr_1162.gif],  

and get the difference equation  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1163.gif].

Take the z-transform of both sides and use the initial condition  [Graphics:../Images/ZTransformIntroModHome_gr_1164.gif]:  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1165.gif],  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1166.gif].  
        
Solve for  [Graphics:../Images/ZTransformIntroModHome_gr_1167.gif]  and get  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1168.gif],  

then use Table 9.1 to find the inverse z-transform   

                    [Graphics:../Images/ZTransformIntroModHome_gr_1169.gif]  

Remark.  The details for the partial fraction expansion are at the bottom of the page.

 

We are done.   

 

Solution 17 (b).

        Using residues we get

                    [Graphics:../Images/ZTransformIntroModHome_gr_1170.gif]  

                    and

                    [Graphics:../Images/ZTransformIntroModHome_gr_1171.gif]  

Thus

                    [Graphics:../Images/ZTransformIntroModHome_gr_1172.gif]  

Therefore,

                    [Graphics:../Images/ZTransformIntroModHome_gr_1173.gif].  

 

We are done.   

Aside.  We can let Mathematica double check our work.

 

Take the z-transform of both sides.

[Graphics:../Images/ZTransformIntroModHome_gr_1174.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1175.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1176.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1177.gif]
[Graphics:../Images/ZTransformIntroModHome_gr_1178.gif]
[Graphics:../Images/ZTransformIntroModHome_gr_1179.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1180.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1181.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1182.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1183.gif]

Find the inverse z-transform.

[Graphics:../Images/ZTransformIntroModHome_gr_1184.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1185.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1186.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1187.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1188.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1189.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1190.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1191.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1192.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1193.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1194.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1195.gif]

          The Maple commands are similar  

[Graphics:../Images/ZTransformIntroModHome_gr_1198.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_1199.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1200.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_1201.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1202.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_1203.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1204.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_1205.gif]

 

Aside.  We can use Mathematica's InverseZTransform subroutine.

[Graphics:../Images/ZTransformIntroModHome_gr_1206.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1207.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1208.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1209.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1210.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1211.gif]

 

[Graphics:../Images/ZTransformIntroModHome_gr_1212.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1213.gif]

          The Maple command is similar  

[Graphics:../Images/ZTransformIntroModHome_gr_1214.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_1215.gif]

 

We are really done.   

Aside.  We can use Mathematica's Rsolve subroutine.

 

[Graphics:../Images/ZTransformIntroModHome_gr_1216.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1217.gif]

          The Maple command is similar  

[Graphics:../Images/ZTransformIntroModHome_gr_1218.gif]  

                                                            [Graphics:../Images/ZTransformIntroModHome_gr_1219.gif]

Aside.  The solution can be written as  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1220.gif].  

 

We are really really done.   

Aside.  We can graph the solution.

 

          [Graphics:../Images/ZTransformIntroModHome_gr_1221.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_1222.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_1223.gif]

  

          [Graphics:../Images/ZTransformIntroModHome_gr_1224.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_1225.gif]     [Graphics:../Images/ZTransformIntroModHome_gr_1226.gif]

                                                                                                                        The sequence   [Graphics:../Images/ZTransformIntroModHome_gr_1227.gif].   

 

 

We are really really really done.   

The Details for the Partial Fractions.   

Aside.  How can we expand   [Graphics:../Images/ZTransformIntroModHome_gr_1228.gif]   into the proper partial fractions?

It is natural to try the command:

[Graphics:../Images/ZTransformIntroModHome_gr_1229.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1230.gif]

But this is not the desired form for using Table 9.1 of z-transforms.

 

Method (i).   Use the following algebra steps  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1231.gif]  

Method (ii).   Find the linear combination of   [Graphics:../Images/ZTransformIntroModHome_gr_1232.gif],  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1233.gif].  

Equate the numerators   [Graphics:../Images/ZTransformIntroModHome_gr_1234.gif],  

and solve the linear system  

                   [Graphics:../Images/ZTransformIntroModHome_gr_1235.gif]  

and get   [Graphics:../Images/ZTransformIntroModHome_gr_1236.gif].   

Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1237.gif].  

Aside.   The Mathematica commands for Method (ii)  are

[Graphics:../Images/ZTransformIntroModHome_gr_1238.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1239.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1240.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1241.gif]

Method (iii).  (For distinct real roots)   First make the substitution   [Graphics:../Images/ZTransformIntroModHome_gr_1242.gif]   in   [Graphics:../Images/ZTransformIntroModHome_gr_1243.gif]   and get  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1244.gif].  

Then use the standard procedure for expanding in partial fractions   

                    [Graphics:../Images/ZTransformIntroModHome_gr_1245.gif].  

Then make the substitution   [Graphics:../Images/ZTransformIntroModHome_gr_1246.gif]   in   [Graphics:../Images/ZTransformIntroModHome_gr_1247.gif]   and get  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1248.gif]  


Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1249.gif].  

Aside.   The Mathematica commands for Method (iii)  are

[Graphics:../Images/ZTransformIntroModHome_gr_1250.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1251.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1252.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1253.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1254.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1255.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1256.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1257.gif]


[Graphics:../Images/ZTransformIntroModHome_gr_1258.gif]

[Graphics:../Images/ZTransformIntroModHome_gr_1259.gif]

Now use the substitution

                    [Graphics:../Images/ZTransformIntroModHome_gr_1260.gif].     
                    
Therefore, the desired form is  

                    [Graphics:../Images/ZTransformIntroModHome_gr_1261.gif].  

 

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell