The Schwarz-Christoffel Transformation

 

Introduction

 

In order to proceed further, we must review the rotational effect of a conformal mapping w = f(z) at a point [Graphics:sc0.txtgr1.gif]. If the contour C has the parameterization z(t) = x(t) + i y(t), then a vector [Graphics:sc0.txtgr2.gif] tangent to C at the point [Graphics:sc0.txtgr3.gif] is

[Graphics:sc0.txtgr5.gif][Graphics:sc0.txtgr4.gif]

The image of C is a contour K given by

[Graphics:sc0.txtgr5.gif][Graphics:sc0.txtgr6.gif]

and a vector [Graphics:sc0.txtgr7.gif] tangent to K at the point [Graphics:sc0.txtgr8.gif] is

[Graphics:sc0.txtgr5.gif][Graphics:sc0.txtgr9.gif]

If the angle of inclination of [Graphics:sc0.txtgr10.gif] is [Graphics:sc0.txtgr11.gif], then the angle of inclination of [Graphics:sc0.txtgr12.gif] is

[Graphics:sc0.txtgr5.gif][Graphics:sc0.txtgr13.gif]

Hence the angle of inclination of the tangent [Graphics:sc0.txtgr14.gif] to C at [Graphics:sc0.txtgr15.gif] is rotated through the angle [Graphics:sc0.txtgr16.gif] to obtain the angle of inclination of the tangent [Graphics:sc0.txtgr17.gif] to K at the point [Graphics:sc0.txtgr18.gif].

 

Theorem 10.6. (Schwarz-Christoffel Formula) Let P be a polygon in the w plane with vertices [Graphics:sc0.txtgr19.gif] and exterior angles [Graphics:sc0.txtgr20.gif], where [Graphics:sc0.txtgr21.gif], for [Graphics:sc0.txtgr22.gif]. There exists a one-to-one conformal mapping w=f(z) from the upper half plane [Graphics:sc0.txtgr24.gif] onto G that satisfies the boundary conditions
[Graphics:sc0.txtgr25.gif]
The derivative is [Graphics:sc0.txtgr26.gif]
and the function f(z) can be expressed as an indefinite integral,
[Graphics:sc0.txtgr27.gif]
where A and B are suitably chosen constants. Two of the points [Graphics:sc0.txtgr28.gif] may be chosen arbitrarily, and the constants A and B determine the size and position of P.

 

 

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(c) John Mathews, 1998, 2006