The Schwarz-Christoffel Transformation

 

Chapter 11. Show that [Graphics:sc2.txtgr1.gif]
maps the upper half plane Im(z) > 0 onto the channel in the right half plane
bounded by the coordinate axes and rays [Graphics:sc2.txtgr2.gif].
The Schwarz-Christoffel formula for [Graphics:sc2.txtgr3.gif] is:

[Graphics:sc2.txtgr5.gif][Graphics:sc2.txtgr4.gif]

Integrate to obtain:

[Graphics:sc2.txtgr5.gif][Graphics:sc2.txtgr6.gif]

This is one, formula for the integral. However, we will use the following form of the integral to continue the computations.

[Graphics:sc2.txtgr5.gif][Graphics:sc2.txtgr7.gif]

The coefficients are [Graphics:sc2.txtgr8.gif], and we obtain

[Graphics:sc2.txtgr5.gif][Graphics:sc2.txtgr9.gif]

A graph for the solution is:

Mapping onto a right-angled channel.

 

 

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(c) John Mathews, 1998, 2006