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for
5.5 Inverse Trigonometric and Hyperbolic Functions
We expressed trigonometric and hyperbolic
functions in Section 5.4 in terms of the exponential
function. In this section we look at their
inverses. When we solve equations such
as
for
z, we will obtain formulas
that involve the logarithm. Because trigonometric and
hyperbolic functions are all periodic, they are many-to-one; hence
their inverses are necessarily multivalued. The formulas for the
inverse trigonometric functions are
We derive the first equation and leave the
others as exercises. If we take a particular branch of the
multivalued function,
,
we have
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which we can also write as
.
Multiplying both sides of this equation
by
gives
,
which is a quadratic equation in terms of
. Using
the quadratic equation to solve for
, we
obtain
,
where the square root is a multivalued function. Taking
the logarithm of both sides and obtain
, then
simplify this and obtain the desired result:
,
where the multivalued logarithm is used. To construct a
specific branch of
,
we must first select a branch of the square root and then select a
branch of the logarithm.
Remark. The function
is
known to be an odd function and therefore
. As
an immediate consequence we have
.
We can now use the trigonometric identity
and
obtain an alternate expression for
:
We mention this derivation because Mathematica uses the second
line for determining the principal value, i.e.
![]()
an we will see shortly that
.
The principal value used by Mathematica for the inverse
trigonometric functions are
When the principal value is
used,
maps
the upper half-plane
onto
a portion of the upper half-plane
that
lies in the vertical strip
. The
image of a rectangular grid in the z
plane is a "spider web" in the w
plane, as Figure 5.10 shows.
![[Graphics:Images/ComplexFunTrigInverseMod_gr_33.gif]](complexfuntriginverse/ComplexFunTrigInverseMod/Images/ComplexFunTrigInverseMod_gr_33.gif)
Figure
5.10 A rectangular grid is mapped onto a spider
web by
.
The derivatives
of arcsin(z), arccos(z),
arctan(z)
We can find the derivatives of any branch of
these functions by using the chain rule:
We get the derivative
of
by
starting with the equation
and
differentiating both sides, using the chain rule:
Then
is
used to get the substitution
for the preceding equation, and we obtain the desired result:
.
Derivation of the other formulas are left as exercises for the
reader.
The Inverse Sine arcsin(z)
. Verify
that the formula
(i)
is correct. (At least for values of z in the upper half
plane
.)
The Inverse Cosine arccos(z)
. Verify
that the formula(s)
(ii
a)
,
(ii
a)
.
are correct. (At least for values of z in the upper half
plane
.)
The Inverse Tangent arctan(z)
. Verify that the formula
(iii)
is correct. (At least for values of z in the upper half
plane
.)
When the principal value is
used,
maps
the upper half-plane
onto
a portion of the upper half-plane
that
lies in the vertical strip
.
![[Graphics:Images/ComplexFunTrigInverseMod_gr_124.gif]](complexfuntriginverse/ComplexFunTrigInverseMod/Images/ComplexFunTrigInverseMod_gr_124.gif)
Figure
5.B The mapping
.
Example 5.11. The
values of
are
given by
.
Using straightforward techniques, we simplify this equation and
obtain
![[Graphics:Images/ComplexFunTrigInverseMod_gr_128.gif]](complexfuntriginverse/ComplexFunTrigInverseMod/Images/ComplexFunTrigInverseMod_gr_128.gif)
where n is an integer. We
observe that
![]()
and then write
, where
n is an integer.
Example
5.12. Suppose that we make specific choices in
equation (5-47) by
selecting
as
the value of the square root
and
using the principal value of the
logarithm. With
, the
result is
,
and the corresponding value of the derivative is given by
![[Graphics:Images/ComplexFunTrigInverseMod_gr_141.gif]](complexfuntriginverse/ComplexFunTrigInverseMod/Images/ComplexFunTrigInverseMod_gr_141.gif)
.
The Inverse Hyperbolic
Functions
The inverse hyperbolic functions
are
To establish the last identity given
above, we start with
and
obtain
![]()
which we solve for
, getting
. Taking
the logarithms of both sides gives
,
which is what we wanted to show.
The Inverse Hyperbolic
Sine arcsinh(z). Verify that the
formula
(iv)
is correct, we can verify this graphically. (At least for
values of z in the upper half plane first quadrant.)
The Inverse Hyperbolic
Cosine arccosh(z) . Verify that the
formula
(v)
is correct, we can verify this graphically. But it
is correct only in
quadrants I and IV.
The Inverse Hyperbolic
Tangent arctanh(z) . Verify that the
formula
(vi)
is correct, we can verify this graphically.
The derivatives of
the inverse hyperbolic functions are
Example
5.13. Calculation reveals that
where n is an integer.
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(c) 2006 John H. Mathews, Russell W. Howell