Example 2.21. Show
that the function
is
discontinuous along the negative real axis.
Solution. Let
denote
a negative real number. We compute the limit as
z approaches
through the upper half-plane
and the limit as z approaches
through the lower half-plane
. In polar coordinates these limits are given
by
, and
.
As the two limits are distinct, the function
is discontinuous at
.
Remark
2.4 Likewise,
is discontinuous at
. The
mappings
,
, and
the branch cut are illustrated in Figure 2.18.
Explore Solution 2.21.
Enter the function ![]()
and
find the limits as z approaches a point on the negative x-axis.
![[Graphics:../Images/ComplexFunBranchMod_gr_72.gif]](../Images/ComplexFunBranchMod_gr_72.gif)
Since the two limits are different, ![]()
is
discontinuous at all points
along
the negative real axis.
![[Graphics:Images/ComplexFunBranchMod_gr_76.gif]](../Images/ComplexFunBranchMod_gr_76.gif)
(a) The
branch
(where
).
![[Graphics:Images/ComplexFunBranchMod_gr_79.gif]](../Images/ComplexFunBranchMod_gr_79.gif)
(b) The
branch
(where
).
Figure
2.18 The branches
and
of
.