Example 2.15. Show
that the function
does
not have a limit as (x,y)
approaches
.
Solution. If we let (x,y)
approach (0,0) along the x
axis, then
.
But if we let (x,y) approach
(0,0) along the line
,
then
.
Because the value of the limit differs depending on how (x,y)
approaches (0,0), we
conclude that
does not have a limit as
approaches
.
Explore Solution 2.15.
Enter the function
.
Find the iterated limit,
.
![[Graphics:../Images/ComplexFunLimitMod_gr_84.gif]](../Images/ComplexFunLimitMod_gr_84.gif)
Find the iterated limit,
.
![[Graphics:../Images/ComplexFunLimitMod_gr_87.gif]](../Images/ComplexFunLimitMod_gr_87.gif)
Find the polar limit
.
![[Graphics:../Images/ComplexFunLimitMod_gr_90.gif]](../Images/ComplexFunLimitMod_gr_90.gif)
![[Graphics:../Images/ComplexFunLimitMod_gr_92.gif]](../Images/ComplexFunLimitMod_gr_92.gif)
So, along all lines through the origin, the limit is 0.
![[Graphics:../Images/ComplexFunLimitMod_gr_94.gif]](../Images/ComplexFunLimitMod_gr_94.gif)
![[Graphics:../Images/ComplexFunLimitMod_gr_95.gif]](../Images/ComplexFunLimitMod_gr_95.gif)
The value of this limit is dependent on the
angle
. Therefore,
does
not have a
limit as (x,y) approaches (0,0).
We can use Mathematica to make a ContourPlot
of u(x,u).
![[Graphics:../Images/ComplexFunLimitMod_gr_99.gif]](../Images/ComplexFunLimitMod_gr_99.gif)
![[Graphics:../Images/ComplexFunLimitMod_gr_100.gif]](../Images/ComplexFunLimitMod_gr_100.gif)
Notice that the contours with the given "c" values all go through
the origin. Hence "many limits" are possible as one
approaches the origin. We see that
does
not have a
(unique) limit
as (x,y) approaches (0,0).
(c) 2006 John H. Mathews, Russell W. Howell