Example 2.11.  Show that the image of the right half plane  [Graphics:Images/ComplexFunLinear_gr_312.gif]  under the linear transformation  [Graphics:Images/ComplexFunLinear_gr_313.gif]  is the half plane  [Graphics:Images/ComplexFunLinear_gr_314.gif].  

Explore Solution 2.11.

Enter the function w = f[z].

[Graphics:../Images/ComplexFunLinear_gr_323.gif]



[Graphics:../Images/ComplexFunLinear_gr_324.gif]

 

 

Solve for the inverse function, i.e. solve for  z  in terms of  w.  

[Graphics:../Images/ComplexFunLinear_gr_325.gif]



[Graphics:../Images/ComplexFunLinear_gr_326.gif]

 

 

To solve for [Graphics:../Images/ComplexFunLinear_gr_327.gif] ,  we use the computations.

[Graphics:../Images/ComplexFunLinear_gr_328.gif]



[Graphics:../Images/ComplexFunLinear_gr_329.gif]

 

 

Or the following commands will also find the solution.

[Graphics:../Images/ComplexFunLinear_gr_330.gif]



[Graphics:../Images/ComplexFunLinear_gr_331.gif]

 

 

Which is the right half plane  [Graphics:../Images/ComplexFunLinear_gr_332.gif]  in the w-plane.  Use Mathematica to graph the transformation.

[Graphics:../Images/ComplexFunLinear_gr_333.gif]



[Graphics:../Images/ComplexFunLinear_gr_334.gif]

[Graphics:../Images/ComplexFunLinear_gr_335.gif]

[Graphics:../Images/ComplexFunLinear_gr_336.gif]

[Graphics:../Images/ComplexFunLinear_gr_337.gif]

We see that the image of the right half plane  [Graphics:../Images/ComplexFunLinear_gr_338.gif]  under the linear transformation  [Graphics:../Images/ComplexFunLinear_gr_339.gif]  is the half plane  [Graphics:../Images/ComplexFunLinear_gr_340.gif].  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2006 John H. Mathews, Russell W. Howell