Example 2.23. For
the transformation
, find
the image of the portion of the right half
plane
that
lies inside the closed disk
.
Explore Solution 2.23.
First, find the image of the right half
plane
.
![[Graphics:../Images/ComplexFunReciprocalMod_gr_128.gif]](../Images/ComplexFunReciprocalMod_gr_128.gif)
This last inequality
is
the same as
and
is the disk of radius 1 centered at w = 1 in
the w-plane.
Now find the image of the interior of the circle
.
![[Graphics:../Images/ComplexFunReciprocalMod_gr_133.gif]](../Images/ComplexFunReciprocalMod_gr_133.gif)
This last inequality
is
the same as
and
is the exterior of the circle with center
and
radius
in
the w-plane.
Use Mathematica to graph the mapping.
![[Graphics:../Images/ComplexFunReciprocalMod_gr_139.gif]](../Images/ComplexFunReciprocalMod_gr_139.gif)
![[Graphics:../Images/ComplexFunReciprocalMod_gr_140.gif]](../Images/ComplexFunReciprocalMod_gr_140.gif)
![[Graphics:../Images/ComplexFunReciprocalMod_gr_141.gif]](../Images/ComplexFunReciprocalMod_gr_141.gif)
![[Graphics:../Images/ComplexFunReciprocalMod_gr_142.gif]](../Images/ComplexFunReciprocalMod_gr_142.gif)
We see that the image of the portion of the right half
plane
that
lies inside the circle
under
the reciprocal transformation
is
the crescent shaped region in the w-plane which is the portion of the
disk
that
lies outside the circle
.
(c) 2006 John H. Mathews, Russell W. Howell