Example  1.5.  To produce an example of which Figure 1.9 is a reasonable illustration, we let  [Graphics:Images/ComplexGeometryMod_gr_61.gif].  Then  [Graphics:Images/ComplexGeometryMod_gr_62.gif]  and  [Graphics:Images/ComplexGeometryMod_gr_63.gif].  Clearly,  [Graphics:Images/ComplexGeometryMod_gr_64.gif];  hence  [Graphics:Images/ComplexGeometryMod_gr_65.gif].  In this case, we can verify the triangle inequality without recourse to computation of square roots because  

        [Graphics:Images/ComplexGeometryMod_gr_66.gif],  
thus
            [Graphics:Images/ComplexGeometryMod_gr_67.gif].  

Explore Solution 1.5.

Compute [Graphics:../Images/ComplexGeometryMod_gr_68.gif].

 

[Graphics:../Images/ComplexGeometryMod_gr_69.gif]



[Graphics:../Images/ComplexGeometryMod_gr_70.gif]

[Graphics:../Images/ComplexGeometryMod_gr_71.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2006 John H. Mathews, Russell W. Howell