Example
1.25. Let
. (b)
Find the exterior of S.
Explore Solution 1.25 (b). Find the exterior of S.
If
then a similar argument will produce an
-neighborhood
of
that
lies entirely in the region
, hence
is
an exterior point of S. It follows that the
exterior of S is the open
region
.
![[Graphics:../Images/ComplexPlaneTopologyMod_gr_165.gif]](../Images/ComplexPlaneTopologyMod_gr_165.gif)
![[Graphics:../Images/ComplexPlaneTopologyMod_gr_168.gif]](../Images/ComplexPlaneTopologyMod_gr_168.gif)