Example 4.21. The
infinite series
has
radius of convergence
Cauchy's root test because
,
hence
.
Explore Solution 4.21.
Enter the formula for the coefficients.
![[Graphics:../Images/ComplexPowerSeriesMod_gr_43.gif]](../Images/ComplexPowerSeriesMod_gr_43.gif)
Use the Cauchy root test and find the limit and then the radius of convergence R.
![[Graphics:../Images/ComplexPowerSeriesMod_gr_45.gif]](../Images/ComplexPowerSeriesMod_gr_45.gif)
The series
will
converge in the disk
.
We can plot some of the partial sums and see that they converge.
Convergence will be faster if we choose a smaller disk
the
following graphs use the smaller disk with
.
![[Graphics:../Images/ComplexPowerSeriesMod_gr_51.gif]](../Images/ComplexPowerSeriesMod_gr_51.gif)
![[Graphics:../Images/ComplexPowerSeriesMod_gr_53.gif]](../Images/ComplexPowerSeriesMod_gr_53.gif)
![[Graphics:../Images/ComplexPowerSeriesMod_gr_55.gif]](../Images/ComplexPowerSeriesMod_gr_55.gif)
![[Graphics:../Images/ComplexPowerSeriesMod_gr_57.gif]](../Images/ComplexPowerSeriesMod_gr_57.gif)
We see that the series
is
converging in the smaller disk
.
Aside. We can let
Mathematica try to determine the "sum" of this series.
Unfortunately, there is no known closed formula. This is an instance where the infinite series is "the answer."