Example
4.22. The infinite
series
has
radius of convergence
by the Cauchy-Hadamard formula. We see this by
calculating
, so
,
hence
.
Explore Solution 4.22.
Enter the formula for the coefficients. There is a formula for the even subscripts and a different formula for the odd subscripts.
![[Graphics:../Images/ComplexPowerSeriesMod_gr_69.gif]](../Images/ComplexPowerSeriesMod_gr_69.gif)
Use the Cauchy-Hadamard formula and find the radius of convergence R.
![[Graphics:../Images/ComplexPowerSeriesMod_gr_71.gif]](../Images/ComplexPowerSeriesMod_gr_71.gif)
The series
has
radius of convergence
by
the Cauchy-Hadamard formula because
.
We can let Mathematica find the sum of this series.
![[Graphics:../Images/ComplexPowerSeriesMod_gr_75.gif]](../Images/ComplexPowerSeriesMod_gr_75.gif)
![[Graphics:../Images/ComplexPowerSeriesMod_gr_76.gif]](../Images/ComplexPowerSeriesMod_gr_76.gif)
Thus we see that f[z] is composed of two "infinite
geometric series"
,
whose radius of convergence are
,
respectively. Hence the radius of convergence of f[z] must
be
.
We can use Mathematica to compute the first few terms in the
Maclaurin series for f[z] and compare them with the formula
that was given.
![[Graphics:../Images/ComplexPowerSeriesMod_gr_81.gif]](../Images/ComplexPowerSeriesMod_gr_81.gif)
We can plot some of the partial sums and see that they converge.
Convergence will be faster if we choose a smaller disk
the
following graphs use the smaller disk with
.
![[Graphics:../Images/ComplexPowerSeriesMod_gr_85.gif]](../Images/ComplexPowerSeriesMod_gr_85.gif)
![[Graphics:../Images/ComplexPowerSeriesMod_gr_87.gif]](../Images/ComplexPowerSeriesMod_gr_87.gif)
![[Graphics:../Images/ComplexPowerSeriesMod_gr_89.gif]](../Images/ComplexPowerSeriesMod_gr_89.gif)
![[Graphics:../Images/ComplexPowerSeriesMod_gr_91.gif]](../Images/ComplexPowerSeriesMod_gr_91.gif)
![[Graphics:../Images/ComplexPowerSeriesMod_gr_93.gif]](../Images/ComplexPowerSeriesMod_gr_93.gif)
![[Graphics:../Images/ComplexPowerSeriesMod_gr_95.gif]](../Images/ComplexPowerSeriesMod_gr_95.gif)