Theorem (First
Fixed Point
Theorem).
Assume that
,
i. e.
is
continuous on . ![]()
Then we have the following conclusions.
(i). If
the range of the mapping
satisfies
for all ![]()
,
then ![]()
has a fixed point in
.
(ii). Furthermore,
suppose that
is defined over ![]()
and that a positive constant ![]()
exists with![]()
for
all ![]()
, then
![]()
has a unique fixed point ![]()
in
.
Proof of (ii).
Now we must show that the solution in (i) is
unique.
By way of contradiction, let us make the additional assumption that
there exists two fixed points
and
.
Now apply the Mean
Value Theorem, and conclude that there exists a
number
so
that
![]()
Next, use the facts that
and
to
simplify this expression and get
.
But this contradicts the hypothesis in (ii) that for
all ![]()
. ![]()
Thus, it is not possible for fixed points to
exist. Therefore,
has a unique fixed point ![]()
in
.
Q. E. D.
(c) John H. Mathews 2004