Example
2. Consider the
integration of the function
over
the fixed interval
. Apply
the various formulas (4) through (7).
![[Graphics:Images/NewtonCotesMod_gr_88.gif]](../Images/NewtonCotesMod_gr_88.gif)
![[Graphics:Images/NewtonCotesMod_gr_89.gif]](../Images/NewtonCotesMod_gr_89.gif)
Trapezoidal
Rule Simpson’s
Rule
![[Graphics:Images/NewtonCotesMod_gr_90.gif]](../Images/NewtonCotesMod_gr_90.gif)
![[Graphics:Images/NewtonCotesMod_gr_91.gif]](../Images/NewtonCotesMod_gr_91.gif)
Simpson’s
3/8
Rule Boole’s
Rule
Solution 2.
For the trapezoidal rule
using
we compute:
Using (8) the Trapezoidal Rule:
Mathematica's Computation is:
For Simpson’s rule
using
we compute:
Using (9) Simpson’s Rule:
Mathematica's Computation is:
For Simpson’s
rule using
we compute:
Using (10) Simpson’s
Rule:
Mathematica's Computation is:
For Boole’s rule
using
we compute:
Using (11) Boole’s Rule:
Mathematica's Computation is:
The true value of the definite integral is
We see that the
approximation 1.30859 from
Boole’s rule is best. The area under each of the Lagrange
polynomials
,
,
,
and
are
shown in the figures for this example.
(c) John H. Mathews 2004