Example 4. An arrow
is shot upward from the origin with an initial velocity
of 300 ft/sec.
Assume that air resistance is proportional to the
power
of the velocity,
, and
use the model
.
Find the velocity and position as a function of time, and plot the
position function.
Solution 4.
Compute the solution using the Runge-Kutta method for second order D.E.'s.
The solution we seek is the first coordinate in the 2D system.
Now we can plot the solution.
![[Graphics:../Images/ProjectileMotionMod_gr_301.gif]](../Images/ProjectileMotionMod_gr_301.gif)
The graph should lie between the ones obtained in examples 2 and
3.
Let's see if this happens.
![[Graphics:../Images/ProjectileMotionMod_gr_308.gif]](../Images/ProjectileMotionMod_gr_308.gif)
The graph does lie where it should lie.
We are done.
Aside. We can "try" to
get an analytic solution.
Clearly, Mathematica is having a difficult time of it.
If the initial condition is not used then Mathematica can go a
little further in the solution.
We should trust our Runge-Kutta solution.
(c) John H. Mathews 2004